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Australia
AS 4100:2020AS 4100:1998

Weld Connection (old AS 4100:1998)

Structural engineers in Australia maintaining designs to AS 4100:1998 who need to check fillet or butt welds under combined shear and tension loading. Suitable for projects where the earlier standard applies.

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What it calculates

Analyse and design fillet weld and butt weld connections to AS 4100:1998. Resolves combined shear and tension into force per unit length of weld and checks against the design capacity with the appropriate reduction factors.

Code standards

  • AS 4100:1998

How it calculates

The Weld Connection (AS 4100:1998) calculator checks fillet and butt weld connections against Clause 9.7 of AS 4100:1998. Given the total shear and tension forces on the connection and the weld geometry, it resolves the demand into force per unit length and compares it to the design capacity.

Force per unit length

The total applied shear force V_w and tension (or compression) force N_w are distributed over the effective weld length l_w:

  • Shear force per unit length: tau_w = V_w / l_w
  • Tension force per unit length: sigma_w = N_w / l_w

The resultant design force per unit length of weld:

v*_w = sqrt(tau_w^2 + sigma_w^2)

Weld capacity (Clause 9.7)

The nominal capacity per unit length v_w depends on the weld type:

Fillet weld: v_w = 0.6 × f_uw × t_t × k_r

where:

  • f_uw = nominal tensile strength of the weld metal (MPa)
  • t_t = throat thickness of the fillet weld (mm)
  • k_r = reduction factor for the length of the lap connection

Butt weld: v_w = f_ub × t_t

where f_ub = nominal tensile strength of the base metal.

Reduction factor for lap connections (k_r)

For lap connections, the force distribution along the weld becomes less uniform as the connection length increases. AS 4100 applies a reduction factor:

  • l_w ≤ 1700 mm: k_r = 1.10 - 0.06 × (l_w / 1000)
  • l_w > 8000 mm: k_r = 0.62
  • Otherwise (1700 mm < l_w ≤ 8000 mm): linear interpolation

For non-lap connections, k_r = 1.0.

Design capacity

The design capacity per unit length of weld is:

v_d = phi × v_w

The capacity factor phi for weld connections to AS 4100:1998 is:

  • phi = 0.8 for fillet welds (SP category)
  • phi = 0.9 for butt welds (SP category)

Utilization check

Utilization = v*_w / v_d ≤ 1.0

When the utilization ratio exceeds 1.0, the weld is overstressed. The throat thickness, weld length, or applied loading must be adjusted.

Design notes

This calculator checks the weld at a single cross-section under uniform loading. For weld groups with moment or torsion, the peak demand location should be identified separately and the maximum force per unit length at that location used as the input. Detailing requirements (minimum throat thickness, end returns, etc.) must be verified by the engineer per AS 4100:1998 Clause 9.8.

Frequently asked questions

What design code does this calculator use?
This calculator checks weld connections to AS 4100:1998 (R2016), Clause 9.7. It evaluates the design force per unit length of weld against the capacity per unit length for fillet welds and butt welds under combined shear and tension loads.
What are the key inputs?
Key inputs are the weld type (fillet or butt weld), throat thickness, effective weld length, weld metal nominal tensile strength f_uw, base metal tensile strength f_ub, total shear force on the connection, and total tension force on the connection. For lap connections, the connection length determines the reduction factor k_r.
What does the calculator check and output?
The calculator resolves the total shear and tension forces into force per unit length components (tau_w and sigma_w), computes the resultant design force per unit length v*_w = sqrt(tau_w^2 + sigma_w^2), and checks this against the design capacity v_d = phi × v_w. The capacity factor phi and reduction factor k_r for long lap connections are reported alongside the utilization ratio.
Can it handle fillet welds under combined shear and bending?
Yes. For connections where the weld group carries both shear and axial (tension or compression) forces, the shear force component tau_w = V_w / l_w and tension component sigma_w = N_w / l_w are combined using the square root of the sum of squares. This approach applies to the weld at the point of highest demand along the effective length.
What weld electrode classifications are supported?
The weld metal tensile strength f_uw is entered directly in MPa, so any electrode classification can be used. For common Australian electrodes, E48XX corresponds to f_uw = 480 MPa. The base metal tensile strength f_ub sets an upper limit on the butt weld capacity.

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